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Space-domain extrapolation

The space-domain finite-differences solution to equation (13) is derived based on a square-root expansion as suggested by Francis Muir (Claerbout, 1985):
\begin{displaymath}
k_\tau \approx \omega a + \omega \frac{ \nu \left ( \frac{ k...
...{\mu-\rho \left ( \frac{ k_\gamma }{ \omega } \right )^2} \;,
\end{displaymath} (16)

where the coefficients $\mu$, $\nu$ and $\rho $ take the form derived in Appendix A:
$\displaystyle \nu$ $\textstyle =$ $\displaystyle - c_1a \left (\frac{b }{a }\right )^2\;,$ (17)
$\displaystyle \mu$ $\textstyle =$ $\displaystyle 1 \;,$ (18)
$\displaystyle \rho$ $\textstyle =$ $\displaystyle c_2 \left (\frac{b }{a }\right )^2\;.$ (19)

In the special case of Cartesian coordinates, $a=s$ and $b=1$, equation (16) takes the familiar form
\begin{displaymath}
k_\tau \approx \omega s - \omega \frac{ \frac{c_1}{s} \left ...
...c_2}{s^2} \left ( \frac{ k_\gamma }{ \omega } \right )^2} \;,
\end{displaymath} (20)

where the coefficients $c_1$ and $c_2$ take different values for different orders of Muir's expansion: $(c_1,c_2)=(0.50,0.00)$ for the $15^\circ $ equation, and $(c_1,c_2)=(0.50,0.25)$ for the $45^\circ$ equation, etc. For extrapolation in Riemannian coordinates, the meaning of $15^\circ $, $45^\circ$ etc is not defined. We use this terminology here to indicate orders of accuracy comparable to the ones defined in Cartesian coordinates.


next up previous [pdf]

Next: Mixed-domain extrapolation Up: Extrapolation kernels Previous: Extrapolation kernels

2007-10-07