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Theoretical part

  1. In class, we derived the following acoustic wave equation for pressure $P(\mathbf{x},t)$:
    \begin{displaymath}
{\frac{1}{V^2(\mathbf{x})}}\,{\frac{\partial^2 P}{\partial t...
...nabla\left(\frac{1}{\rho(\mathbf{x})}\right) \cdot \nabla P\;.
\end{displaymath} (1)

    Using the connection between the pressure and displacement, derive the acoustic wave equation for the displacement vector $\mathbf{u}(\mathbf{x},t)$:
    $\displaystyle \rho(\mathbf{x})\,\frac{\partial^2 \mathbf{u}}{\partial t^2} = - \nabla P = \nabla \left(K(\mathbf{x})\nabla \cdot \mathbf{u}\right)$     (2)
    $\displaystyle {\frac{1}{V^2(\mathbf{x})}}\,{\frac{\partial^2 \mathbf{u}}{\parti...
...mathbf{u}) +
\frac{\nabla\cdot\mathbf{u}}{K(\mathbf{x})}\; \nabla K(\mathbf{x})$     (3)

    Thanks to the Helmholtz's theorem, we can consider the displacement vector field to be curl free for the acoustic propagation:
    $\displaystyle {\frac{1}{V^2(\mathbf{x})}}\,{\frac{\partial^2 \mathbf{u}}{\parti...
...mathbf{u}) +
\frac{\nabla\cdot\mathbf{u}}{K(\mathbf{x})}\; \nabla K(\mathbf{x})$     (4)

  2. Consider a geometrical wave representation in the vicinity of a wavefront
    \begin{displaymath}
{\mathbf{u}(\mathbf{x},t)} = \mathbf{a}(\mathbf{x})\,f\left(t-T(\mathbf{x})\right)
\end{displaymath} (5)

    and derive partial differential equations for the traveltime function $T(\mathbf{x})$ and the vector amplitude $\mathbf{a}(\mathbf{x})$.
    $\displaystyle \ddot{\mathbf{u}} = \mathbf{a}\;\ddot{f}$     (6)
    $\displaystyle \nabla\cdot\mathbf{u} = f\;(\nabla\cdot\mathbf{a}) - \dot{f}\;(\mathbf{a}\cdot\nabla T)$     (7)
    $\displaystyle \nabla^2\;\mathbf{u} = f\;\nabla^2\mathbf{a} - 2\dot{f}\;(\nabla ...
...thbf{a}
+ \ddot{f}\;(\nabla T)^2\,\mathbf{a} - \mathbf{a}\;\dot{f}\;\nabla^2\,T$     (8)


        $\displaystyle \left[S^2(\mathbf{x})-(\nabla T)^2\right]\mathbf{a}\;\ddot{f}(t-T(\mathbf{x}))$ (9)
      $\textstyle +$ $\displaystyle \left[2(\nabla T \cdot \nabla)\mathbf{a}+\mathbf{a}\;\nabla^2\,T
...
...t\nabla T}{K(\mathbf{x})}\; \nabla K(\mathbf{x})\right]\dot{f}(t-T(\mathbf{x}))$ (10)
      $\textstyle =$ $\displaystyle \left[\nabla^2\mathbf{a}+ \frac{\nabla\cdot \mathbf{a}}{K(\mathbf{x})}\; \nabla K(\mathbf{x}) \right]{f}(t-T(\mathbf{x}))$ (11)

    The term in front of $\ddot{f}$ is zero to enable discontinuities to propagate and is the eikonal equation. The term in front of $\dot{f}$ is zero, if we neglect the lower order term in $f$ in the framework of high frequencies (WKBJ), and this is the transport equation.
  3. Assuming that the geometrical wave propagates in the direction of the traveltime gradient
    \begin{displaymath}
{\mathbf{a}(\mathbf{x})} = A(\mathbf{x})\,V(\mathbf{x})\,\nabla T
\end{displaymath} (12)

    show that the amplitude equation can take the conservative form
    $\displaystyle \nabla \cdot \left(\rho(\mathbf{x})\,V^2(\mathbf{x})\,A^2(\mathbf{x})\,\nabla T\right) = 0$     (13)
    $\displaystyle \nabla \cdot \left(K(\mathbf{x})\,A^2(\mathbf{x})\,\nabla T\right) = 0$     (14)
    $\displaystyle A^2(\mathbf{x})\left[\nabla K \cdot \nabla T\right] + 2K(\mathbf{...
...\nabla A \cdot \nabla T\right] + K(\mathbf{x})\;A^2(\mathbf{x})\;\nabla^2 T = 0$     (15)

    On the other hand, with the transport equation:
    $\displaystyle 2(\nabla T \cdot \nabla)(A(\mathbf{x})\,\mathbf{u}_T)
+ A(\mathbf...
...
+ A(\mathbf{x})
\frac{S(\mathbf{x})}{K(\mathbf{x})}\; \nabla K(\mathbf{x}) = 0$     (16)

    where $\mathbf{u}_T$ is the unitary vector along the traveltime gradient direction. By performing the dot product with the traveltime gradient vector and multiplying by $A(\mathbf{x})\;K(\mathbf{x})\;V(\mathbf{x})$:
        $\displaystyle 2\,K(\mathbf{x})\; A^2(\mathbf{x})\; V(\mathbf{x}) \left[(\nabla T \cdot \nabla)\;\mathbf{u}_T\right]\cdot\nabla T$ (17)
      $\textstyle +$ $\displaystyle 2\,K(\mathbf{x})\; A(\mathbf{x})\left[\nabla A \cdot \nabla T\right]$ (18)
      $\textstyle +$ $\displaystyle A^2(\mathbf{x})\,K(\mathbf{x})\;\nabla^2T$ (19)
      $\textstyle +$ $\displaystyle A^2(\mathbf{x})\; \nabla K(\mathbf{x})\cdot\nabla T = 0$ (20)

    The first term is zero since the gradient of the unitary vector along the traveltime gradient direction is zero.
  4. The displacement amplitude continuation along a ray is given by equation
    \begin{displaymath}
\left\vert\mathbf{a}_1\right\vert = \left\vert\mathbf{a}_...
...eft(\frac{\rho_0\,V_0\,J_0}{\rho_1\,V_1\,J_1}\right)^{1/2}\;,
\end{displaymath} (21)

    thanks to the Gauss theorem, where $J_0$ and $J_1$ are the corresponding geometrical spreading factors.
  5. (EXTRA CREDIT) Consider the elastic wave equation
    \begin{displaymath}
\rho\,\ddot{u}_i = C_{ijkl,j}\,u_{k,l} + C_{ijkl}\,u_{k,lj}\;
\end{displaymath} (22)

    in the case of an isotropic elasticity
    \begin{displaymath}
C_{ijkl} = \lambda\,\delta_{ij}\,\delta_{kl} +
\mu\,(\delta_{ik}\,\delta_{jl} + \delta_{il}\,\delta_{jk})\;.
\end{displaymath} (23)

    Using the geometrical representation (5) with the P-wave polarization given by equation (12), show that the corresponding amplitude equations are similar to equations (13) and (21).


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Next: Computational part Up: Homework 3 Previous: Prerequisites

2008-09-29