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Inverse of a $2\times 2$ matrix


$\displaystyle \bold A ^{-1} \quad\quad\quad\quad \bold A \quad\quad$ $\textstyle =$ $\displaystyle \ \quad\bold I$ (110)
$\displaystyle \frac{1}{ad-bc}
\left[
\begin{array}{rr}
d & -b \\
-c & a
\end{array}\right]
\quad
\left[
\begin{array}{rr}
a & b \\
c & d
\end{array}\right]$ $\textstyle =$ $\displaystyle \left[
\begin{array}{rr}
1 & 0 \\
0 & 1
\end{array}\right]$ (111)




2014-12-01